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Maths
Decimal Numbers
Question:
4^n = 1024 ആയാൽ 4^(n-2 ) എത്ര ?
A
4
B
16
C
64
D
256
Answer:
C. 64
Explanation:
4^5 = 1024 , n = 5 </br> 4^3 = 64
Related Questions:
0.1 x 0.01 x 1001-ന് തുല്ല്യമായതേത് ?
(5^4 × 5^3) / 5^7 ?
52.7÷.....= 0.527
122.992 - ? = 57.76 + 31.1
0.58 - 0.0058 =