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Question:
A55 m
B110 m
C220 m
D230 m
Answer:
If the radius of the outer circle is R1 and radius of the inner circle is R2 R1R2=2322 \frac {R1}{R2} = \frac {23}{22} R2R1=2223 R1 = R2 +5 R2+5R2=2322 \frac {R2 + 5}{R2} = \frac {23}{22} R2R2+5=2223 R2 = 110
diameter of the inner circle = 220
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